Chemistry · Unit 5 of 10 Physical Behavior of Matter
Physical Behavior of Matter Notes · Unit 5 of 10

Physical Behavior of Matter

Mixtures and solutions, energy and heat, gases, phase changes, intermolecular forces. The big one.

0The Ten Units

Chemistry on the Regents is organized into ten major units. Unit 5 is the one your teacher probably calls the "big one" because it pulls in ideas from atomic structure, the periodic table, and bonding, and turns them into rules about how mixtures, solutions, gases, and phase changes actually behave.

I. Atomic Structure
II. The Periodic Table
III. Stoichiometry
IV. Chemical Bonding
V. Physical Behavior of Matter
VI. Equilibrium
VII. Organic Chemistry
VIII. Oxidation-Reduction
IX. Acids, Bases, and Salts
X. Nuclear Chemistry

By the end of this page you will be able to classify any sample of matter, separate mixtures the right way, calculate concentrations, work the combined gas law, read solubility and vapor-pressure curves, walk through a heating curve and explain what energy is doing in every segment, and identify hydrogen bonding from a molecule's formula.

1Classifying Matter

Every sample of matter is either a pure substance or a mixture. A pure substance has only one kind of particle. A mixture has two or more, just blended together.

Element
A pure substance made of only one kind of atom. Listed on the periodic table. Examples: $\text{Cu}$, $\text{O}_2$, $\text{Fe}$.
Compound
A pure substance made of two or more elements chemically bonded in fixed ratios. Examples: $\text{H}_2\text{O}$, $\text{NaCl}$, $\text{CO}_2$.
Homogeneous mixture
Same composition throughout. Also called a solution. Looks like one phase. Example: salt water.
Heterogeneous mixture
Different composition in different spots. You can see the parts. Example: salad, oil and water, sand in water.

A pure substance has one set of fixed properties (boiling point, density, melting point). A mixture has a range, because the proportions can change. That is the reason "salt water" boils at slightly different temperatures depending on how salty it is.

Particle diagram check

Regents loves particle diagrams. The rule is simple. Different colored circles mean different elements. Two circles bonded together mean a compound. A bunch of unconnected single circles all the same color mean an element. Toggle the diagram below to see all four cases plus the three phases.

Particle Diagram Builder
2Separating Mixtures

Mixtures can be pulled apart by physical means. You do not need a chemical reaction. Pick the method that exploits whatever property is different between the parts.

Filtration
Separates by particle size (or by solubility, when one part dissolves and the other does not). A filter holds back the bigger particles. Example: sand from salt water.
Distillation
Separates by boiling point. Heat the mixture, the lower-bp component evaporates first, then condenses back to liquid in a cooler tube. Example: alcohol from water, salt from salt water.
Chromatography
Separates by polarity and how strongly each part sticks to a stationary medium versus how strongly it travels with a moving solvent. Example: separating dyes in ink.

A pure substance cannot be separated by physical means. If you can boil, filter, or chromatograph it apart, it was a mixture.

3Solutions, Solute, and Solvent

A solution is a homogeneous mixture. The component you have less of (and that gets dissolved) is the solute. The component you have more of (and that does the dissolving) is the solvent. In salt water, salt is the solute and water is the solvent.

Like dissolves like. Polar solutes dissolve in polar solvents. Nonpolar solutes dissolve in nonpolar solvents. Polar and nonpolar do not mix.

Water is polar, so it dissolves polar things (sugar, salt) and ionic compounds. Oil is nonpolar, so it does not dissolve in water but does dissolve other nonpolar things like grease.
Solubility curve (Table G)

Table G on the Reference Tables shows how many grams of a solute will dissolve in 100 g of water at a given temperature. The line is the saturation point. Below the line, unsaturated. On the line, saturated. Above the line, supersaturated.

Most solid solutes get more soluble as temperature goes up. Most gas solutes get less soluble as temperature goes up. That is why a warm soda goes flat faster than a cold one.

Table G Solubility Curve Reader
temperature: 50°C
Worked example: reading Table G
Question. How many grams of $\text{KNO}_3$ can dissolve in 100 g of water at $60^\circ\text{C}$?
Find the curve. Pick the curve labeled $\text{KNO}_3$.
Trace up. Start at $60^\circ\text{C}$ on the x-axis, go up to the curve.
Read across. About 107 g.
Meaning. At $60^\circ\text{C}$, 100 g of water can hold about 107 g of $\text{KNO}_3$ before it stops dissolving.
4Concentration: Molarity and ppm

"Concentration" is just how much solute is in a given amount of solution. Two ways the Regents asks for it:

Molarity (M) $= \dfrac{\text{moles of solute}}{\text{liters of solution}}$
ppm $= \dfrac{\text{grams of solute}}{\text{grams of solution}} \times 1{,}000{,}000$

Both formulas live on Table T. Use molarity for concentrated solutions (lab work, titrations). Use ppm for very dilute solutions (drinking-water contaminants, trace pollutants).

Molarity / ppm Calculator
Enter values to compute.
Worked example: molarity
Question. What is the molarity of a solution that contains 2 moles of $\text{NaCl}$ in 0.5 L of solution?
Set up. $M = \dfrac{2 \text{ mol}}{0.5 \text{ L}}$
Solve. $M = 4 \text{ M}$, read as "4 molar."
Worked example: ppm
Question. A 1000 g sample of water contains 0.05 g of fluoride. What is the concentration in ppm?
Set up. $\text{ppm} = \dfrac{0.05}{1000} \times 1{,}000{,}000$
Solve. $\text{ppm} = 50$. The water has 50 ppm fluoride.
5Boiling-Point Elevation and Freezing-Point Depression

When you dissolve a solute in a solvent, two things happen to that solvent's phase change temperatures:

Boiling point goes UP. Solute particles get in the way of solvent particles trying to escape into the gas phase. You need more energy (more heat) to boil.

Freezing point goes DOWN. Solute particles disrupt the orderly lattice that solid would form. You have to cool further before freezing wins out.

Real-world examples. Salting roads in winter lowers the freezing point of water so ice melts. Adding salt to pasta water raises the boiling point a tiny bit (and seasons the pasta). The bigger the concentration, the bigger the shift.

Practice 1: Mixtures and Solutions

Try each one before opening the answer.

1. Classify each of the following as element, compound, homogeneous mixture, or heterogeneous mixture: (a) iron filings, (b) tap water, (c) chocolate chip cookie, (d) carbon dioxide.
(a) Element. (b) Homogeneous mixture (water plus dissolved minerals). (c) Heterogeneous mixture (chips visible). (d) Compound ($\text{CO}_2$ is two elements bonded).
2. Which separation method would you use to remove sand from salt water?
Filtration first. Sand is insoluble, so a filter catches it. Then distillation if you also want to recover the salt.
3. A solution at $30^\circ\text{C}$ contains 30 g of $\text{KNO}_3$ in 100 g of water. Use Table G logic: is it saturated, unsaturated, or supersaturated?
Unsaturated. At $30^\circ\text{C}$, $\text{KNO}_3$ saturation is about 45 g per 100 g water. 30 g is below the line, so the solvent could still dissolve more.
4. Calculate the molarity of a solution made by dissolving 0.5 mol of $\text{HCl}$ in enough water to make 250 mL of solution.
2 M. $M = \dfrac{0.5 \text{ mol}}{0.25 \text{ L}} = 2$. Convert mL to L first.
5. Will adding salt to water raise or lower the freezing point? Explain in one sentence.
Lower it. Salt particles get in the way of water trying to form an orderly solid lattice, so the water has to be cooled further before it freezes.
6Forms of Energy

Energy is the ability to do work or cause change. It comes in several forms. The Regents recognizes six.

Chemical
Stored in the bonds between atoms. Released or absorbed during reactions. A battery, gasoline, food.
Electrical
Energy carried by moving charges. Current through a wire, lightning.
Electromagnetic
Light. Radio waves, visible light, x-rays. Travels as waves with no medium needed.
Thermal (heat)
Total kinetic energy of moving particles in a sample of matter.
Mechanical
Energy of moving objects (kinetic) or position (potential). A swinging pendulum.
Nuclear
Energy stored in the nucleus of an atom. Released in fission and fusion. Covered in Unit 10.
7Heat, Temperature, and Kinetic Energy

These three get mixed up constantly. They are not the same.

Heat
A form of energy. Heat is energy in transit. Measured in joules ($\text{J}$) or calories ($\text{cal}$).
Temperature
A measurement of average kinetic energy. Measured in Celsius or Kelvin. Temperature is not a form of energy.
Kinetic energy
Energy of motion. The faster the particles move (translation, rotation, vibration), the higher the temperature.

Heat always flows from hot to cold. Always. It does not flow uphill on its own. When two objects touch, faster particles bang into slower particles, transferring kinetic energy until the temperatures match. That final state is called thermal equilibrium.

Celsius and Kelvin

Both scales measure temperature. Kelvin starts at absolute zero (the lowest possible temperature, where all particle motion stops). Celsius starts at the freezing point of water. The conversion is on Table T.

$K = ^\circ\text{C} + 273$

Examples. Water freezes at $0^\circ\text{C}$ or 273 K. Water boils at $100^\circ\text{C}$ or 373 K. Room temperature is about $20^\circ\text{C}$ or 293 K.

8Endothermic vs Exothermic

A reaction or phase change is described by which way energy flows.

Exothermic. Releases heat to the surroundings. Surroundings warm up. Examples: combustion, freezing water, condensing steam.

Endothermic. Absorbs heat from the surroundings. Surroundings cool down. Examples: melting ice, boiling water, photosynthesis, dissolving ammonium nitrate (an instant cold pack).

A way to remember it. Exo means out, like an exit. Heat exits the system. Endo means in. Heat enters the system.

9Calculating Heat Energy

Three formulas live on Table T. Which one you use depends on whether the substance is changing temperature or changing phase.

Temperature change: $q = mc\Delta T$
Melting / freezing: $q = mH_f$
Boiling / condensing: $q = mH_v$
$q$
Heat absorbed or released, in joules.
$m$
Mass of the substance, in grams.
$c$
Specific heat capacity. For water, $c = 4.18 \text{ J/g}\cdot^\circ\text{C}$.
$\Delta T$
Change in temperature: $T_{\text{final}} - T_{\text{initial}}$.
$H_f$
Heat of fusion. For water, $H_f = 334 \text{ J/g}$.
$H_v$
Heat of vaporization. For water, $H_v = 2260 \text{ J/g}$.

Notice the pattern. If the substance is changing temperature, you use $c$ and $\Delta T$. If the substance is changing phase, the temperature stays constant, so you use $H_f$ or $H_v$ instead. Use the right one or your numbers will be way off.

Worked example: heating water
Question. How much heat is needed to raise 50 g of water from $25^\circ\text{C}$ to $75^\circ\text{C}$?
Pick formula. Temperature change, no phase change. Use $q = mc\Delta T$.
Plug in. $q = (50)(4.18)(75 - 25) = (50)(4.18)(50)$
Solve. $q = 10{,}450 \text{ J}$, or about 10.5 kJ.
Worked example: melting ice
Question. How much heat is needed to melt 50 g of ice at $0^\circ\text{C}$?
Pick formula. Phase change at constant temperature. Use $q = mH_f$.
Plug in. $q = (50)(334)$
Solve. $q = 16{,}700 \text{ J}$.
Heat Energy Calculator
Enter values to compute heat.
Practice 2: Energy and Heat
1. Convert $25^\circ\text{C}$ to Kelvin.
298 K. $K = 25 + 273 = 298$.
2. A reaction releases heat to the surroundings. Endothermic or exothermic?
Exothermic. Heat exits the system.
3. How many joules of heat are needed to raise 200 g of water from $20^\circ\text{C}$ to $80^\circ\text{C}$? ($c = 4.18 \text{ J/g}\cdot^\circ\text{C}$.)
50,160 J. $q = (200)(4.18)(60) = 50{,}160 \text{ J}$.
4. How much heat is needed to vaporize 25 g of water at $100^\circ\text{C}$? ($H_v = 2260 \text{ J/g}$.)
56,500 J. $q = (25)(2260) = 56{,}500 \text{ J}$.
5. Two metal blocks are at $80^\circ\text{C}$ and $20^\circ\text{C}$. They are placed in contact. Which way does heat flow?
From the hot block to the cold block. Heat always flows from higher temperature to lower temperature, until both reach the same final temperature.
10Ideal Gas Particles

Real gases are messy. To make the math work, chemists invented an idealized model called the ideal gas. An ideal gas particle has three properties:

  • Particles move in random, straight-line motion until they collide.
  • Particles have negligible volume. Treat them as points.
  • Particles have no attractive forces between them. They do not stick to each other.

No real gas obeys these rules perfectly. But a real gas behaves most like an ideal gas at low pressure and high temperature. Why? Low pressure means particles are far apart, so their tiny volume does not matter. High temperature means particles move fast, so weak attractive forces are easy to overcome.

The opposite is also true. At high pressure (squeezed close together) and low temperature (slow moving), real gases deviate the most from ideal behavior, because attractions and particle volume start to matter. Hydrogen and helium come closest to behaving ideally because their particles are small and weakly attracted.

11Combined Gas Law

Pressure, volume, and temperature of a fixed amount of gas are linked by one equation on Table T.

$\dfrac{P_1 V_1}{T_1} = \dfrac{P_2 V_2}{T_2}$
Critical rule. Temperature must be in Kelvin. If the problem gives Celsius, convert first ($K = ^\circ\text{C} + 273$). Use 0 K and you divide by zero. Use Celsius and your ratios are wrong.

Pressure can be in any unit (kPa, atm, mmHg) as long as both sides match. Volume the same way (L or mL). Just keep the units consistent across the two sides.

The relationships hidden in this one equation:

  • Boyle (T constant): $P_1 V_1 = P_2 V_2$. Squeeze a balloon, pressure goes up.
  • Charles (P constant): $\dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}$. Heat a balloon, it expands.
  • Gay-Lussac (V constant): $\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2}$. Heat a sealed can, pressure goes up.
Worked example
Question. A gas at $27^\circ\text{C}$ occupies 2.0 L at 100 kPa. What volume will it occupy at $127^\circ\text{C}$ and 50 kPa?
Convert. $T_1 = 27 + 273 = 300 \text{ K}$. $T_2 = 127 + 273 = 400 \text{ K}$.
Set up. $\dfrac{(100)(2.0)}{300} = \dfrac{(50)(V_2)}{400}$
Solve. $V_2 = \dfrac{(100)(2.0)(400)}{(300)(50)} = \dfrac{80{,}000}{15{,}000} \approx 5.3 \text{ L}$.
Sanity check. Lower pressure means more volume. Higher temperature means more volume. Both effects pull volume up, so 5.3 L (versus 2.0) makes sense.
Combined Gas Law Solver (leave one cell blank)
Initial
P₁
V₁
T₁ (K)
Final
P₂
V₂
T₂ (K)
Fill in five of the six values, leave one blank, and the solver will fill it in. Temperatures must be in Kelvin.
Practice 3: Gases
1. Name the three properties of an ideal gas particle.
Random straight-line motion. Negligible volume. No attractive forces between particles.
2. Under what conditions does a real gas behave most like an ideal gas?
Low pressure and high temperature. Particles are far apart and moving fast.
3. A gas occupies 4.0 L at 200 K. What volume does it occupy at 400 K, with pressure constant?
8.0 L. $V_1/T_1 = V_2/T_2$. $V_2 = (4.0)(400)/200 = 8.0$ L. Doubling absolute temperature at constant pressure doubles the volume.
4. Why must temperature be in Kelvin for gas-law problems?
Kelvin is an absolute scale that starts at zero motion. Celsius can be negative, which would give nonsense ratios. The gas laws describe how particle motion scales with absolute temperature, so only Kelvin works.
5. A gas has $P_1 = 200$ kPa, $V_1 = 1.5$ L, $T_1 = 300$ K. After a change, $P_2 = 100$ kPa and $T_2 = 600$ K. Find $V_2$.
6.0 L. $V_2 = \dfrac{P_1 V_1 T_2}{T_1 P_2} = \dfrac{(200)(1.5)(600)}{(300)(100)} = 6.0$ L.
12States of Matter and Kinetic Molecular Theory

All matter is made of tiny particles in constant motion. That idea is the kinetic molecular theory, or KMT. The state of a sample (solid, liquid, gas) depends on how much kinetic energy those particles carry and how strongly the IFAs pull them together.

The KMT in one paragraph. Particles in matter are always moving. The hotter the substance, the faster they move. Their motion is countered by intermolecular forces of attraction (IFAs) trying to pull them together. Whichever wins decides the state.

Solid: IFAs win. Particles vibrate but stay locked.
Liquid: a tie. Particles slip past each other but stay close.
Gas: kinetic energy wins. Particles fly apart and fill the container.
Comparing the three states
SolidLiquidGas
ShapeDefiniteTakes shape of containerFills container
VolumeDefiniteDefiniteIndefinite
Particle motionVibrate in placeSlide past each otherFast, random, straight-line
Particle spacingTightly packed in a latticeClose, irregularFar apart
IFA strengthStrongestModerateNegligible
DensityHighHigh (slightly less)Very low
CompressibilityVery lowVery lowHigh
KE of particlesLowestModerateHighest

Water is a famous exception on density. Solid water (ice) is less dense than liquid water, which is why ice floats. Hydrogen bonds force water molecules into an open, hexagonal lattice when they freeze, leaving extra empty space inside the solid.

A note on plasma

A fourth state, plasma, exists at extremely high temperatures (stars, lightning, fluorescent bulbs). Particles have so much kinetic energy that electrons strip off and the substance becomes a soup of charged particles. The Regents will sometimes mention plasma but rarely test it in depth.

13Phase Changes in Detail

There are six named phase changes. Three add energy and lift the substance up the phase ladder. Three release energy and drop it down.

Solid → Liquid
Fusion (melting)
Endothermic. Heat goes into loosening IFAs in the lattice. Particles can now flow.
Liquid → Gas
Vaporization (boiling)
Endothermic. Heat breaks all remaining IFAs. Particles fly free.
Solid → Gas
Sublimation
Endothermic. Both fusion and vaporization at once. Examples: dry ice ($\text{CO}_2$), iodine, mothballs.
Liquid → Solid
Freezing
Exothermic. Particles lose KE and get trapped by IFAs. Heat is released.
Gas → Liquid
Condensation
Exothermic. Particles slow enough for IFAs to grab them. Dew on grass, steam on a cold mirror.
Gas → Solid
Deposition
Exothermic. Frost on a window forms when water vapor skips the liquid phase entirely.

Pattern. Going up the phase ladder (solid → liquid → gas) is endothermic and needs heat in. Going down is exothermic and gives heat out.

Why temperature stays constant during a phase change

When ice melts at $0^\circ\text{C}$, you can keep dumping heat in but the thermometer reads $0^\circ\text{C}$ until the last bit melts. That confuses students. Where does the heat go if not into a higher reading?

The heat is going into potential energy, not kinetic. Specifically, it pulls apart the IFAs holding the lattice together. Once the IFAs are broken (the substance has fully melted), heat starts being absorbed as kinetic energy again, and the temperature climbs.

During a phase change, every joule you add goes into breaking attractions. None of it speeds the particles up. Temperature, which measures average kinetic energy, stays flat.
Why $H_v$ is much larger than $H_f$

For water, $H_f = 334$ J/g but $H_v = 2260$ J/g. Vaporizing takes almost seven times more energy than melting. Why?

Melting only loosens IFAs enough to let particles slide. Most attractions are still in play. Vaporizing has to break every IFA. The particles have to gain enough kinetic energy to fly apart and stop interacting. That is a much bigger energy bill.

This is why a steam burn (gas condensing on your skin) is far worse than a hot-water burn at the same temperature. Condensing steam dumps 2260 J/g of latent heat into your skin before the water itself even starts to cool.

Boiling vs evaporation

Both turn liquid into gas. The difference:

  • Evaporation happens at the surface, at any temperature. Only the fastest molecules at the top escape. The liquid cools as a result, which is why sweat cools you down.
  • Boiling happens throughout the liquid, at the boiling point. Bubbles of vapor form inside the liquid. It happens when the liquid's vapor pressure equals atmospheric pressure (covered later in card 17).
Melting and freezing point are the same temperature

A substance's melting point and freezing point are the same number. Water melts and freezes at $0^\circ\text{C}$. The difference is which direction heat is flowing. Add heat at that temperature and you melt. Remove heat at that temperature and you freeze. Both processes can happen simultaneously at equilibrium (which is exactly what is happening in a glass of ice water).

14Kinetic Energy and Potential Energy on a Heating Curve

A heating curve is a graph of temperature versus time as you steadily add heat to a substance. It has five segments. The flat segments are where the trick lives.

Sloped segments. Temperature is rising. The substance is in one phase and heating up. Kinetic energy increases. Potential energy stays the same.

Flat segments. Temperature is constant. The substance is changing phase. Kinetic energy stays the same. The added heat is going entirely into potential energy, breaking the attractions between particles.

This is the most-tested point in the whole unit. During a phase change, KE does not increase. The heat is going into PE. Read that twice. The Regents loves to trip students who say "kinetic energy goes up the whole time."

Heating Curve Walker
Solid heating up
Phase
Solid
Kinetic energy
Increasing
Potential energy
Constant
Cooling curves

A cooling curve is the same graph in reverse. Slopes go down. The flat segments are still phase changes, but now the substance is releasing heat to its surroundings (freezing and condensation, both exothermic).

15Calculating Heat Across a Heating Curve

Real heating-curve problems usually ask for the total heat needed to take a substance from a starting state to a final state. The trick is to break the path into segments and use the right formula for each one. Sloped segments get $q = mc\Delta T$. Flat segments get $q = mH_f$ or $q = mH_v$.

The five-segment recipe (solid below freezing → gas above boiling):
  1. Heat the solid up to the melting point: $q_1 = m \, c_{\text{solid}} \, \Delta T$
  2. Melt it (constant temperature): $q_2 = m H_f$
  3. Heat the liquid up to the boiling point: $q_3 = m \, c_{\text{liquid}} \, \Delta T$
  4. Boil it (constant temperature): $q_4 = m H_v$
  5. Heat the gas up to the final temperature: $q_5 = m \, c_{\text{gas}} \, \Delta T$
Total heat = $q_1 + q_2 + q_3 + q_4 + q_5$.

If your start or end state stops in the middle of the curve, you only sum the segments your path actually crosses. For example, water at $25^\circ\text{C}$ to steam at $100^\circ\text{C}$ is just steps 3 and 4.

Worked example: 50 g of ice at $-10^\circ\text{C}$ to steam at $120^\circ\text{C}$

Use water values from Table T (extended): $c_{\text{ice}} = 2.10 \text{ J/g}\cdot^\circ\text{C}$, $c_{\text{water}} = 4.18$, $c_{\text{steam}} = 2.01$, $H_f = 334$ J/g, $H_v = 2260$ J/g.

1. Heat ice from -10 to 0. $q_1 = (50)(2.10)(0 - (-10)) = (50)(2.10)(10) = 1050 \text{ J}$.
2. Melt at 0. $q_2 = (50)(334) = 16{,}700 \text{ J}$.
3. Heat water from 0 to 100. $q_3 = (50)(4.18)(100) = 20{,}900 \text{ J}$.
4. Boil at 100. $q_4 = (50)(2260) = 113{,}000 \text{ J}$.
5. Heat steam from 100 to 120. $q_5 = (50)(2.01)(20) = 2010 \text{ J}$.
Total. $1050 + 16{,}700 + 20{,}900 + 113{,}000 + 2010 = 153{,}660 \text{ J}$, about 154 kJ.
Where the energy went. The two phase-change steps (melt + boil = 129,700 J) account for about 84% of the total. Phase changes dominate the energy budget.
Reading a heating curve from a graph

If a problem hands you a heating-curve graph, you can read off both phase-change temperatures (the y-values of the two flat segments) and even rank $H_f$ vs $H_v$ qualitatively (longer flat segment = bigger heat absorbed).

Graph-reading checklist.
  1. Lower flat segment temperature = melting point.
  2. Upper flat segment temperature = boiling point.
  3. Longer flat segment = more heat absorbed in that phase change.
  4. Steeper slope on a heating segment = lower specific heat in that phase (less heat needed per degree).
  5. Two flat segments and three sloped segments = full solid-to-gas walk.

A cooling curve flips this. The two flat segments now mark condensation (higher temperature) and freezing (lower temperature). Both are exothermic: the substance releases heat to its surroundings.

16Intermolecular Forces of Attraction (IFAs)

Inside a molecule, atoms are held together by chemical bonds (covalent or ionic). Between separate molecules, weaker forces still pull them toward each other. These are intermolecular forces of attraction, or IFAs.

IFAs are what hold a liquid together as a liquid. Stronger IFAs mean a higher boiling point, because more energy is needed to pull molecules apart into the gas phase.

IFA strength by phase: Solids > Liquids > Gases.

Solid particles are locked in place because IFAs hold them tightly. Liquid particles can flow but still feel each other. Gas particles barely interact at all (which is why gases approximate ideal behavior).
Hydrogen bonds

A hydrogen bond is the strongest type of IFA. It happens when a molecule contains a hydrogen atom bonded directly to F, O, or N. The exposed proton on hydrogen attracts to a lone pair on a neighboring molecule's F, O, or N.

Hydrogen bond rule: H bonded to F, O, or N

Common examples: $\text{HF}$, $\text{H}_2\text{O}$, $\text{NH}_3$

Hydrogen bonding explains why water has such a high boiling point compared to other small molecules ($\text{H}_2\text{S}$, $\text{H}_2\text{Se}$, etc. are gases at room temperature even though they are heavier). It is also why water has such high surface tension and why ice floats.

If a molecule has H but not bonded to F, O, or N (for example, $\text{CH}_4$, $\text{HCl}$), it does not form hydrogen bonds. Common Regents trap.

17Vapor Pressure and Boiling (Table H)

Vapor pressure is the pressure exerted by a liquid's vapor in equilibrium with the liquid. Higher temperature means more particles have enough energy to escape, so vapor pressure rises with temperature.

A liquid boils when its vapor pressure equals atmospheric pressure. Standard atmospheric pressure is 101.3 kPa.

On Table H, follow each substance's curve and find where it crosses 101.3 kPa. That x-value is the substance's normal boiling point.

A liquid with weaker IFAs has a higher vapor pressure at any given temperature (its molecules escape more easily). It also has a lower boiling point.

Table H ranking (weakest IFAs to strongest IFAs):
propanone < ethanol < water < ethanoic acid

So at any temperature, propanone has the highest vapor pressure. Ethanoic acid has the lowest. The order of normal boiling points is the reverse: propanone $\sim 56^\circ\text{C}$, ethanol $\sim 78^\circ\text{C}$, water $100^\circ\text{C}$, ethanoic acid $\sim 118^\circ\text{C}$.
Table H Vapor Pressure Reader
temperature: 60°C
Worked example: reading Table H
Question. If atmospheric pressure drops to 80 kPa (high altitude), what is water's new boiling point?
Find the curve. Water curve.
Find the pressure. 80 kPa on the y-axis.
Read across to the curve. Down to the x-axis.
Answer. About $93^\circ\text{C}$. Water boils at a lower temperature when atmospheric pressure is lower. That is why pasta takes longer to cook on a mountain.
18Why Water is the Most Useful Polar Covalent Compound

Almost every interesting physical property of water comes from one fact: water is a polar covalent molecule, and a small one. That polarity, combined with water's ability to form hydrogen bonds (covered in Unit 4 and card 16), explains its specific heat, its solubility, and why we use it for cooling almost everything.

The chain of cause and effect:
  1. O is much more electronegative than H ($\Delta$EN $\approx$ 1.24). So each O-H bond is polar covalent.
  2. The molecule is bent (two lone pairs on O), so the bond dipoles do not cancel. The whole molecule is polar.
  3. H bonded to O satisfies the H-bond rule. So water molecules hydrogen-bond to each other (and to many other things).
  4. That dense H-bond network is responsible for nearly every "weird" property of water.
Why water has such a high specific heat

Water's specific heat is $c = 4.18 \text{ J/g}\cdot^\circ\text{C}$, one of the highest of any substance. For comparison: aluminum is 0.90, copper is 0.39, iron is 0.45. To raise a gram of water by one degree takes about 5 times as much energy as the same for aluminum.

The reason traces straight back to hydrogen bonds. When you add heat to water, only some of it goes into speeding up the molecules (kinetic energy, which is what the thermometer reads). A big chunk goes into pulling against the hydrogen-bond network, stretching and breaking H-bonds, then letting them re-form. That "wasted" energy is stored in potential energy of the bond network, not in faster motion. So the temperature rises slowly per joule added.

Without H-bonds, water's specific heat would be much lower. Methane ($\text{CH}_4$), nonpolar and no H-bonds, has $c \approx 2.2 \text{ J/g}\cdot^\circ\text{C}$ as a gas. Ethanol, with some H-bonding but less dense, is $c \approx 2.44 \text{ J/g}\cdot^\circ\text{C}$ as a liquid. Water's 4.18 stands out specifically because every water molecule can form up to 4 H-bonds.
Liquid cooling and why engineers love water

High specific heat makes water the best general-purpose coolant on Earth. Examples:

  • Car radiators. Hot engine, cooled by water (mixed with antifreeze to extend the liquid range). Water absorbs huge amounts of heat per degree before getting too hot.
  • Computer water cooling. Gaming PCs and data centers loop water through CPU/GPU blocks because air alone is not dense or heat-hungry enough.
  • Nuclear and fossil-fuel power plants. All use water as the working fluid: it absorbs reactor heat, boils to steam, drives a turbine, condenses back.
  • The ocean. Earth's climate is moderated by oceans. They absorb summer heat slowly and release it in winter slowly, smoothing out temperature swings on coastal areas.
  • Sweating. Mammals lose heat through evaporating water on skin. Each gram that evaporates carries away 2260 J (water's $H_v$). Massive cooling per drop.
Why polarity drives "like dissolves like" for water

Polar water molecules can pry apart polar and ionic solutes. Each $\text{Na}^+$ ion in salt water is surrounded by water molecules with their oxygen ends ($\delta^-$) pointed at it. Each $\text{Cl}^-$ is surrounded by water with hydrogen ends ($\delta^+$) pointed at it. The water-ion attractions overcome the ion-ion attractions in the salt lattice. The salt dissolves.

What dissolves in water:
  • Ionic compounds (most salts, like $\text{NaCl}$, $\text{KCl}$, $\text{MgSO}_4$)
  • Polar molecular compounds (sugar, ethanol, ammonia)
  • Compounds that can hydrogen-bond with water (alcohols, acids)
What does NOT dissolve in water:
  • Nonpolar molecules (oil, gasoline, methane, $\text{O}_2$ partially)
  • The reason: water would have to break its own H-bonds to make room, with no payoff. So it does not.
Worked example: heat absorbed by water in a radiator
Setup. A car radiator holds 5000 g of water. The engine raises the water from $80^\circ\text{C}$ to $95^\circ\text{C}$ before the radiator dumps it.
Heat absorbed by water. $q = mc\Delta T = (5000)(4.18)(15) = 313{,}500 \text{ J}$, about 314 kJ.
Compare. If the radiator used aluminum (c = 0.90) instead, the same volume could only carry $q = (5000)(0.90)(15) = 67{,}500 \text{ J}$. Water carries about 4.6 times more heat for the same mass and temperature swing.
Takeaway. That capacity is why your engine does not melt. Hydrogen bonds soak up the kinetic energy before the temperature actually climbs.
Quick callouts

A few more water-property highlights tied to its polar covalent / H-bonding nature:

  • $H_v = 2260$ J/g is among the highest of common liquids. Why sweat cools. Why steam burns are so bad.
  • $H_f = 334$ J/g is also unusually high. Why ice in a drink keeps the drink cold for so long.
  • Ice floats. Hexagonal lattice from H-bonding leaves empty space, lowering density.
  • Surface tension. H-bonds at the surface pull inward, creating a skin you can float a paper clip on.
  • Universal solvent. Cell biology, blood, oceans, weather, agriculture, every chemistry lab.
Practice 4: Phase Changes, IFAs, Vapor Pressure
1. Name the phase change for each: (a) solid to gas, (b) gas to liquid, (c) liquid to solid.
(a) Sublimation. (b) Condensation. (c) Freezing.
2. While a substance is melting at its melting point, what happens to its kinetic energy? Its potential energy?
Kinetic energy stays the same (temperature is constant). Potential energy increases, because the heat being added is going into breaking attractions between particles, not into faster motion.
3. Which of these molecules form hydrogen bonds: $\text{H}_2\text{O}$, $\text{CH}_4$, $\text{NH}_3$, $\text{HCl}$, $\text{HF}$?
$\text{H}_2\text{O}$, $\text{NH}_3$, and $\text{HF}$. All three have H bonded to F, O, or N. $\text{CH}_4$ has H bonded to carbon (no). $\text{HCl}$ has H bonded to chlorine (no, even though Cl is electronegative, the rule is specifically F, O, or N).
4. On Table H, which substance has the strongest intermolecular forces of attraction?
Ethanoic acid. It has the lowest vapor pressure at any given temperature and the highest boiling point on the chart, both of which signal the strongest IFAs.
5. A flat segment on a heating curve at $0^\circ\text{C}$ on water tells you what is happening?
The water is melting (or freezing). $0^\circ\text{C}$ is the melting/freezing point of water. The flat segment means temperature is constant during the phase change.
6. A real gas behaves least like an ideal gas under what conditions? Why?
High pressure and low temperature. Particles are squeezed close together (volume of each particle starts to matter) and move slowly (attractive forces start to matter), so the ideal-gas assumptions break down.
Practice 5: Heating Curves and Phase Changes

These questions all hinge on what is happening at each segment of a heating or cooling curve. Use the walker in card 14 to visualize before answering.

1. A heating curve has a flat segment at $0^\circ\text{C}$ and a longer flat segment at $100^\circ\text{C}$. What does the longer flat segment tell you?
The substance absorbs more heat at $100^\circ\text{C}$ than at $0^\circ\text{C}$. Both flat segments are phase changes (melting and boiling, here for water). The longer one means more total heat went in, which corresponds to a bigger $H_v$ compared to $H_f$. For water, $H_v = 2260$ J/g vs $H_f = 334$ J/g, almost seven times bigger.
2. A 30 g sample of ice at $0^\circ\text{C}$ is heated until it becomes water at $0^\circ\text{C}$. How much heat was absorbed? ($H_f = 334$ J/g.)
10,020 J. Phase change at constant temperature: $q = m H_f = (30)(334) = 10{,}020 \text{ J}$. No $\Delta T$ term because temperature is constant during melting.
3. Identify what is happening to kinetic energy and potential energy on each part of a heating curve: (a) sloped segment, (b) flat segment.
(a) Sloped: kinetic energy is increasing, potential energy is constant. The substance is in one phase and warming up. (b) Flat: kinetic energy is constant, potential energy is increasing. The substance is changing phase, with the heat going into breaking IFAs.
4. Compute the total heat needed to take 100 g of water from $25^\circ\text{C}$ liquid to steam at $100^\circ\text{C}$. ($c_{\text{water}} = 4.18$, $H_v = 2260$.)
257,350 J, about 257 kJ.
Step 1 (heat liquid 25 to 100): $q_1 = (100)(4.18)(75) = 31{,}350 \text{ J}$.
Step 2 (boil at 100): $q_2 = (100)(2260) = 226{,}000 \text{ J}$.
Total: $31{,}350 + 226{,}000 = 257{,}350 \text{ J}$. Most of the energy goes into the phase change.
5. A cooling curve shows a substance going from gas to solid. Which two segments will be flat, what phase changes do they represent, and are they endothermic or exothermic?
Two flat segments: condensation and freezing. Condensation (gas to liquid) at the higher temperature, freezing (liquid to solid) at the lower one. Both are exothermic because the substance is releasing heat to its surroundings as it cools.
6. Why does a steam burn at $100^\circ\text{C}$ cause more damage than a hot-water burn at $100^\circ\text{C}$?
Steam at $100^\circ\text{C}$ has to condense on your skin first, releasing 2260 J/g of latent heat ($H_v$) before it even starts to cool. Hot water at $100^\circ\text{C}$ skips that step. Same temperature, but steam delivers far more energy.
7. On a particle-level basis, explain why solids have stronger IFAs than gases.
In a solid, particles are tightly packed and barely move, so IFAs have time and proximity to act. In a gas, particles are far apart and moving fast, so any attraction barely registers before the particles separate again. The stronger the IFAs in a substance, the higher its melting and boiling points.
8. A heating curve for an unknown substance shows a melting plateau at $50^\circ\text{C}$ and a boiling plateau at $200^\circ\text{C}$. What are the substance's melting and boiling points, and at room temperature ($20^\circ\text{C}$) what state is it in?
MP = $50^\circ\text{C}$, BP = $200^\circ\text{C}$. At $20^\circ\text{C}$ (below the melting point) the substance is a solid.
9. During a heating-curve flat segment, a student says "the heat is being lost because the temperature is not going up." Why is this wrong?
The heat is not lost. It is going into potential energy, breaking the IFAs that hold particles together. Temperature only measures average kinetic energy, so it stays flat while PE rises. Once the phase change is complete, additional heat starts going back into KE and the temperature climbs again.
10. A 25 g sample of water at $100^\circ\text{C}$ is fully boiled into steam at $100^\circ\text{C}$. Then a separate 25 g sample of water at $100^\circ\text{C}$ is cooled to ice at $0^\circ\text{C}$. Which process releases more total energy in absolute value? ($c = 4.18$, $H_f = 334$, $H_v = 2260$.)
Boiling absorbs more energy than the full cool-and-freeze process releases.
Boiling: $q = m H_v = (25)(2260) = 56{,}500 \text{ J}$ absorbed.
Cool 100 to 0: $q = (25)(4.18)(100) = 10{,}450 \text{ J}$ released.
Freeze at 0: $q = m H_f = (25)(334) = 8{,}350 \text{ J}$ released.
Total cool+freeze = $18{,}800 \text{ J}$ released, vs $56{,}500 \text{ J}$ for the boil. The single phase change at the top of the curve is bigger than the entire descent on the rest. That is how dominant $H_v$ is.
Up Next

Unit 6 is Equilibrium, the natural sequel to phase changes and saturation. Coming soon.